Optimal. Leaf size=104 \[ -\frac {\sin ^3(c+d x) (a-a \cos (c+d x))^3}{6 a^5 d}-\frac {\sin ^5(c+d x)}{10 a^2 d}-\frac {\sin ^3(c+d x) \cos (c+d x)}{8 a^2 d}-\frac {3 \sin (c+d x) \cos (c+d x)}{16 a^2 d}+\frac {3 x}{16 a^2} \]
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Rubi [A] time = 0.31, antiderivative size = 104, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 6, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.286, Rules used = {3872, 2875, 2870, 2669, 2635, 8} \[ -\frac {\sin ^5(c+d x)}{10 a^2 d}-\frac {\sin ^3(c+d x) (a-a \cos (c+d x))^3}{6 a^5 d}-\frac {\sin ^3(c+d x) \cos (c+d x)}{8 a^2 d}-\frac {3 \sin (c+d x) \cos (c+d x)}{16 a^2 d}+\frac {3 x}{16 a^2} \]
Antiderivative was successfully verified.
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Rule 8
Rule 2635
Rule 2669
Rule 2870
Rule 2875
Rule 3872
Rubi steps
\begin {align*} \int \frac {\sin ^6(c+d x)}{(a+a \sec (c+d x))^2} \, dx &=\int \frac {\cos ^2(c+d x) \sin ^6(c+d x)}{(-a-a \cos (c+d x))^2} \, dx\\ &=\frac {\int \cos ^2(c+d x) (-a+a \cos (c+d x))^2 \sin ^2(c+d x) \, dx}{a^4}\\ &=-\frac {(a-a \cos (c+d x))^3 \sin ^3(c+d x)}{6 a^5 d}-\frac {\int (-a+a \cos (c+d x)) \sin ^4(c+d x) \, dx}{2 a^3}\\ &=-\frac {(a-a \cos (c+d x))^3 \sin ^3(c+d x)}{6 a^5 d}-\frac {\sin ^5(c+d x)}{10 a^2 d}+\frac {\int \sin ^4(c+d x) \, dx}{2 a^2}\\ &=-\frac {\cos (c+d x) \sin ^3(c+d x)}{8 a^2 d}-\frac {(a-a \cos (c+d x))^3 \sin ^3(c+d x)}{6 a^5 d}-\frac {\sin ^5(c+d x)}{10 a^2 d}+\frac {3 \int \sin ^2(c+d x) \, dx}{8 a^2}\\ &=-\frac {3 \cos (c+d x) \sin (c+d x)}{16 a^2 d}-\frac {\cos (c+d x) \sin ^3(c+d x)}{8 a^2 d}-\frac {(a-a \cos (c+d x))^3 \sin ^3(c+d x)}{6 a^5 d}-\frac {\sin ^5(c+d x)}{10 a^2 d}+\frac {3 \int 1 \, dx}{16 a^2}\\ &=\frac {3 x}{16 a^2}-\frac {3 \cos (c+d x) \sin (c+d x)}{16 a^2 d}-\frac {\cos (c+d x) \sin ^3(c+d x)}{8 a^2 d}-\frac {(a-a \cos (c+d x))^3 \sin ^3(c+d x)}{6 a^5 d}-\frac {\sin ^5(c+d x)}{10 a^2 d}\\ \end {align*}
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Mathematica [A] time = 0.95, size = 111, normalized size = 1.07 \[ \frac {\cos ^4\left (\frac {1}{2} (c+d x)\right ) \sec ^2(c+d x) \left (-480 \sin (c+d x)+30 \sin (2 (c+d x))+80 \sin (3 (c+d x))-90 \sin (4 (c+d x))+48 \sin (5 (c+d x))-10 \sin (6 (c+d x))+25 \tan \left (\frac {c}{2}\right )+360 d x\right )}{480 a^2 d (\sec (c+d x)+1)^2} \]
Antiderivative was successfully verified.
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fricas [A] time = 1.43, size = 71, normalized size = 0.68 \[ \frac {45 \, d x - {\left (40 \, \cos \left (d x + c\right )^{5} - 96 \, \cos \left (d x + c\right )^{4} + 50 \, \cos \left (d x + c\right )^{3} + 32 \, \cos \left (d x + c\right )^{2} - 45 \, \cos \left (d x + c\right ) + 64\right )} \sin \left (d x + c\right )}{240 \, a^{2} d} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.26, size = 113, normalized size = 1.09 \[ \frac {\frac {45 \, {\left (d x + c\right )}}{a^{2}} + \frac {2 \, {\left (45 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{11} - 1025 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} - 174 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} - 594 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 255 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 45 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )}}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 1\right )}^{6} a^{2}}}{240 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.63, size = 222, normalized size = 2.13 \[ \frac {3 \left (\tan ^{11}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{8 d \,a^{2} \left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )^{6}}-\frac {205 \left (\tan ^{9}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{24 d \,a^{2} \left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )^{6}}-\frac {29 \left (\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{20 d \,a^{2} \left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )^{6}}-\frac {99 \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{20 d \,a^{2} \left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )^{6}}-\frac {17 \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{8 d \,a^{2} \left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )^{6}}-\frac {3 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{8 d \,a^{2} \left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )^{6}}+\frac {3 \arctan \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{8 d \,a^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [B] time = 0.55, size = 292, normalized size = 2.81 \[ -\frac {\frac {\frac {45 \, \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} + \frac {255 \, \sin \left (d x + c\right )^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}} + \frac {594 \, \sin \left (d x + c\right )^{5}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{5}} + \frac {174 \, \sin \left (d x + c\right )^{7}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{7}} + \frac {1025 \, \sin \left (d x + c\right )^{9}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{9}} - \frac {45 \, \sin \left (d x + c\right )^{11}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{11}}}{a^{2} + \frac {6 \, a^{2} \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}} + \frac {15 \, a^{2} \sin \left (d x + c\right )^{4}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{4}} + \frac {20 \, a^{2} \sin \left (d x + c\right )^{6}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{6}} + \frac {15 \, a^{2} \sin \left (d x + c\right )^{8}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{8}} + \frac {6 \, a^{2} \sin \left (d x + c\right )^{10}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{10}} + \frac {a^{2} \sin \left (d x + c\right )^{12}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{12}}} - \frac {45 \, \arctan \left (\frac {\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1}\right )}{a^{2}}}{120 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 3.75, size = 107, normalized size = 1.03 \[ \frac {3\,x}{16\,a^2}-\frac {-\frac {3\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{11}}{8}+\frac {205\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^9}{24}+\frac {29\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^7}{20}+\frac {99\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5}{20}+\frac {17\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3}{8}+\frac {3\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}{8}}{a^2\,d\,{\left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+1\right )}^6} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \frac {\int \frac {\sin ^{6}{\left (c + d x \right )}}{\sec ^{2}{\left (c + d x \right )} + 2 \sec {\left (c + d x \right )} + 1}\, dx}{a^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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